2y^2-4y+3=

Solution for 2y^2-4y+3= equation:

Simplifying
2y2 + -4y + 3 = 0

Reorder the terms:
3 + -4y + 2y2 = 0

Solving
3 + -4y + 2y2 = 0

Solving for variable 'y'.

Begin completing the square.  Divide all terms by
2 the coefficient of the squared term: 

Divide each side by '2'.
1.5 + -2y + y2 = 0

Move the constant term to the right:

Add '-1.5' to each side of the equation.
1.5 + -2y + -1.5 + y2 = 0 + -1.5

Reorder the terms:
1.5 + -1.5 + -2y + y2 = 0 + -1.5

Combine like terms: 1.5 + -1.5 = 0.0
0.0 + -2y + y2 = 0 + -1.5
-2y + y2 = 0 + -1.5

Combine like terms: 0 + -1.5 = -1.5
-2y + y2 = -1.5

The y term is -2y.  Take half its coefficient (-1).
Square it (1) and add it to both sides.

Add '1' to each side of the equation.
-2y + 1 + y2 = -1.5 + 1

Reorder the terms:
1 + -2y + y2 = -1.5 + 1

Combine like terms: -1.5 + 1 = -0.5
1 + -2y + y2 = -0.5

Factor a perfect square on the left side:
(y + -1)(y + -1) = -0.5

Can't calculate square root of the right side.

The solution to this equation could not be determined.